How the voltage requirements into watts? [voltage requirements] [dvd drive]
Q: My DVD drive says its necessary for voltage . but it does not amps! So how do I convert this to watts?
“+5 V + / -5% and less than 100 p ripple MVP voltage
977 503 12 V + / -5% and less than 200 MVP-p ripple voltage
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Re:Nowhere does your text indicate you need to know the power consumption typically measured in Watts.
+/- 5% is typical (allowed) variances in computer power supplies. The ripple voltage is indicative of remnants of AC and/or spurious harmonic artifacts from switching power conversion. Good power supplies typically will have less than 50 mV peak to peak ripple. Too much ripple can cause problems in circuits performing pulse code modulation operations even with good implementation of Cross Interleave Reed-Solomon Code.
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Re:Originally posted by: guy
Originally posted by: guy
Watt = Volts * Amps
(If my brain is working right today that is…)
Actually isn't it P=I^2*R so it would be Watt = Volts * Amps^2
(my brain might not be working right today either tho…)
P=I^2 *R, but V=I*R, so P=I*V or Amps*Volts
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Re:Originally posted by: guy
Originally posted by: guy
Watt = Volts * Amps
(If my brain is working right today that is…)
Actually isn't it P=I^2*R so it would be Watt = Volts * Amps^2
(my brain might not be working right today either tho…)
Basic physics dudes, both are correct…
DVD drives typically consume between 10-30W, depending on how fast it's spinning and the exact model.
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Re:As guy noted, you need more info, axeman.
For DC, Ohm's laws:
E=IR
P=EI
Ez Dvd Copy.
Re:Originally posted by: guy
Watt = Volts * Amps
(If my brain is working right today that is…)
Actually isn't it P=I^2*R so it would be Watt = Volts * Amps^2
(my brain might not be working right today either tho…)
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Re:need resistance too… i think theres 2 diff simple equations
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Re:Watt = Volts * Amps
(If my brain is working right today that is…)
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Re:You don't have enough information.
guy
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Tags: dvd drive, voltage requirements